$$2 \mathrm{H}_2 \mathrm{O} \rightarrow 4 \mathrm{H}^{+}+\mathrm{O}_2+4 e^{-}$$
Based on the above equation, answer the following questions
(a) Where does this reaction take place in plants?
(b) What is the significance of this reaction?
(a) The reaction takes place in reaction centre PS II, located on the inner surface of thylakoid membrane. It is known as water splitting centre where electrons are extracted from water. The $\mathrm{Mn}^{+}$and $\mathrm{Cl}^{-}$ions catalyse this reaction.
(b) Splitting of water is an important event in photosynthesis as
(i) It releases molecular oxygen as byproduct of photosynthesis and is the significant source of oxygen in air, or is essential for all living beings on earth.
(ii) Hydrogen ions produced, are utilised in reducing NADP to NADPH, a strong reducing agent.
(iii) The electrons released are transferred from PS II to PS I through a series of electron carriers thus, creating a gradient for the synthesis of ATP.
(a) NADP reductase enzyme is located on .............. .
(b) Breakdown of proton gradient leads to release of ............ .
(a) NADP reductase enzyme is located on the outer side of thylakoid membrane. It is bounded to the thylakoid membrance in light and becomes free in stroma during dark.
(b) ATP Molecules The movement of $\mathrm{H}^{+}$ions across the membrane is coupled with the formation of ATP synthesis in presence of enzyme ATP synthase.
$$\begin{aligned} 3 \mathrm{CO}_2+9 \mathrm{ATP}+6 \mathrm{NADPH}+\text { water } \longrightarrow & \text { Glyceraldehyde } 3-\text { phosphate } \\ + & 9 \mathrm{ADP}+6 \mathrm{NADP}^{+}+8 \mathrm{Pi} . \end{aligned}$$
Analyse the above reaction and answer the following questions
(a) How many molecules of ATP and NADPH are required to fix one molecule of $\mathrm{CO}_2$ ?
(b) Where in the chloroplast does this process occur?
(a) 2 molecules of ATP for phosphorylation and two molecules of NADPH for reduction are required per $\mathrm{CO}_2$ molecule fixed.
(b) The calvin cycle occurs in the stroma of the chloroplast.