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67
MCQ (Single Correct Answer)

Assertion (A) Both rhombic and monoclinic sulphur exist as $S_8$ but oxygen exists as $\mathrm{O}_2$.

Reason (R) 0xygen forms $p \pi$ - $p \pi$ multiple bond due to small size and small bond length but $p \pi-p \pi$ bonding is not possible in sulphur.

A
Both Assertion and Reason are correct statements, and Reason is the correct explanation of the Assertion.
B
Both Assertion and Reason are correct statements, and Reason is not the correct explanation of the Assertion.
C
Assertion is correct, but Reason is wrong statement.
D
Assertion is wrong but Reason is correct statement.
E
Both Assertion and Reason are wrong statements.
68
MCQ (Single Correct Answer)

Assertion (A) NaCl reacts with concentrated $\mathrm{H}_2 \mathrm{SO}_4$ to give colourless fumes with pungent smell. But on adding $\mathrm{MnO}_2$ the fumes become greenish yellow.

Reason $(\mathrm{R}) \mathrm{MnO}_2$ oxidises HCl to chlorine gas which is greenish yellow.

A
Both Assertion and Reason are correct statements, and Reason is the correct explanation of the Assertion.
B
Both Assertion and Reason are correct statements, and Reason is not the correct explanation of the Assertion.
C
Assertion is correct, but Reason is wrong statement.
D
Assertion is wrong but Reason is correct statement.
E
Both Assertion and Reason are wrong statements.
69
MCQ (Single Correct Answer)

Assertion (A) $\mathrm{SF}_6$ cannot be hydrolysed but $\mathrm{SF}_4$ can be.

Reason (R) Six F-atoms in $\mathrm{SF}_6$ prevent the attack of $\mathrm{H}_2 \mathrm{O}$ on sulphur atom of $\mathrm{SF}_6$.

A
Both Assertion and Reason are correct statements, and Reason is the correct explanation of the Assertion.
B
Both Assertion and Reason are correct statements, and Reason is not the correct explanation of the Assertion.
C
Assertion is correct, but Reason is wrong statement.
D
Assertion is wrong but Reason is correct statement.
E
Both Assertion and Reason are wrong statements.
70
Subjective

An amorphous solid " $A$ " burns in air to form a gas " $B$ " which turns lime water milky. The gas is also produced as a by-product during roasting of sulphide ore. This gas decolourises acidified aqueous $\mathrm{KMnO}_4$ solution and reduces $\mathrm{Fe}^{3+}$ to $\mathrm{Fe}^{2+}$. Identify the solid " A " and the gas " B " and write the reactions involved.

Explanation

Since, the by-product of roasting of sulphide ore is $\mathrm{SO}_2$, so A is $\mathrm{S}_8$ ' $A$ ' $=\mathrm{S}_8{ }^{\prime} \cdot B$ ' $=\mathrm{SO}_2$

Reactions

(i) $\mathrm{S}_8+8 \mathrm{O}_2 \xrightarrow{\Delta} 8 \mathrm{SO}_2$

(ii) $\mathrm{Ca}(\mathrm{OH})_2+\mathrm{SO}_2 \longrightarrow \mathrm{CaSO}_3+\mathrm{H}_2 \mathrm{O}$

(iii) $\underset{\text { (violet) }}{2 \mathrm{MnO}_4^{-}}+5 \mathrm{SO}_2+2 \mathrm{H}_2 \mathrm{O} \longrightarrow 5 \mathrm{SO}_4^{2-}+4 \mathrm{H}^{+}+\underset{\text { (Colourless) }}{2 \mathrm{Mn}^{2+}}$

(iv) $2 \mathrm{Fe}^{3+}+\mathrm{SO}_2+2 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{Fe}^{2-}+\mathrm{SO}_4^{2-}+4 \mathrm{H}^{+}$

71
Subjective

On heating lead (II) nitrate gives a brown gas " $A$ ". The gas " $A$ " on cooling changes to colourless solid " $B$ ". Solid " $B$ " on heating with NO changes to a blue solid ' $C$ '. Identify ' $A$ ', ' $B$ ' and ' $C$ ' and also write reactions involved and draw the structures of ' $B$ ' and ' $C$ '.

Explanation

$\mathrm{Pb}\left(\mathrm{NO}_3\right)_2$ on heating produces a brown coloured gas which may be $\mathrm{NO}_2$. Since, on reaction with $\mathrm{N}_2 \mathrm{O}_4$ and on heating it produces $\mathrm{N}_2 \mathrm{O}_3$ and $\mathrm{N}_2 \mathrm{O}_4$ respectively.

Structures