Match the compounds/elements given in Column I with uses given in Column II.
| Column I (Compound/element) |
Column II (Use) |
||
|---|---|---|---|
| A. | Lanthanoid oxide | 1. | Production of iron alloy |
| B. | Lanthanoid | 2. | Television screen |
| C. | Misch metal | 3. | Petroleum cracking |
| D. | Magnesium based alloy is constituent of | 4. | Lanthanoid metal + iron |
| E. | Mixed oxides of lanthanoids are employed | 5. | Bullets |
| 6. | X-ray screen |
A. $\rightarrow(2)$ B. $\rightarrow$ (1) C. $\rightarrow(4)$ D. $\rightarrow$ (5) E. $\rightarrow(3)$
| (Compound/element) | (Use) | ||
|---|---|---|---|
| A. | Lanthanoid oxide | 1. | Television screen |
| B. | Lanthanoid | 2. | Production of iron alloy |
| C. | Misch metal | 3. | Lanthanoid metal + iron |
| D. | Magnesium based alloy is constituent of | 4. | Bullets |
| E. | Mixed oxides of lanthanoids are employed | 5. | Petroleum cracking |
Match the properties given in Column I with the metals given in Column II.
| Column I (Property) |
Column II (Metal) |
||
|---|---|---|---|
| A. | An element which can show +8 oxidation state | 1. | Mn |
| B. | 3d block element that can show upto +7 oxidation state | 2. | Cr |
| C. | 3d block element with highest melting point | 3. | Os |
| 4. | Fe |
A. $\rightarrow(3)$ B. $\rightarrow$ (1) C. $\rightarrow(2)$
A. Osmium is an element which can show +8 oxidation state.
B. $3 d$ block element that can show upto +7 oxidation state is manganese.
C. $3 d$ block element with highest melting point is chromium.
Match the statements given in Column I with the oxidation states given in Column II.
| Column I |
Column II |
||
|---|---|---|---|
| A. | Oxidation state of Mn in MnO$_2$ is | 1. | +2 |
| B. | Most stable oxidation state of Mn is | 2. | +3 |
| C. | Most stable oxidation state of Mn in oxides is | 3. | +4 |
| D. | Characteristic oxidation state of lanthanoid is | 4. | +5 |
| 5. | +7 |
A. $\rightarrow(3)$ B. $\rightarrow$ (1) C. $\rightarrow$ (5) D. $\rightarrow(2)$
A. Oxidation state of Mn in $\mathrm{MnO}_2$ is +4 .
B. Most stable oxidation state of Mn is +2 .
C. Most stable oxidation state of Mn in oxides is +7 .
D. Characteristic oxidation state of lanthanoids is +3 .
Match the solutions given in Column I and the colours given in Column II.
| Column I (Aqueous solution of salt) |
Column II (Colour) |
||
|---|---|---|---|
| A. | $\mathrm{FeSO_4 . 7H_2O}$ | 1. | Green |
| B. | $\mathrm{NiCl_2 . 4H_2O}$ | 2. | Light pink |
| C. | $\mathrm{MnCl_2 4H_2O}$ | 3. | Blue |
| D. | $\mathrm{CoCl_2 . 6H_2O}$ | 4. | Pale green |
| E. | $\mathrm{Cu_2Cl_2}$ | 5. | Pink |
| 6. | Colourless |
A. $\rightarrow$ (4) B. $\rightarrow$ (1) C. $\rightarrow(2)$ D. $\rightarrow$ (5) E. $\rightarrow$ (6)
| (Aqueous solution of salt) | (Colour) | ||
|---|---|---|---|
| A. | $\mathrm{FeSO_4 . 7H_2O}$ | 1. | Pale green |
| B. | $\mathrm{NiCl_2 . 4H_2O}$ | 2. | Green |
| C. | $\mathrm{MnCl_2 4H_2O}$ | 3. | Light pink |
| D. | $\mathrm{CoCl_2 . 6H_2O}$ | 4. | Pink |
| E. | $\mathrm{Cu_2Cl_2}$ | 5. | Colourless |
Match the property given in Column I with the element given in Column II.
| Column I (Property) |
Column II (Element) |
||
|---|---|---|---|
| A. | Lanthanoid which shows +4 oxidation state | 1. | Pm |
| B. | Lanthanoid which can show +2 oxidation state | 2. | Ce |
| C. | Radioactive lanthanoid | 3. | Lu |
| D. | Lanthanoid which has $4f^7$ electronic configuration in +3 oxidation state | 4. | Eu |
| E. | Lanthanoid which has $4f^{14}$ electronic configuration in +3 oxidation state | 5. | Gd |
| 6. | Dy |
A. $\rightarrow(2)$ B. $\rightarrow$ (4) C. $\rightarrow$ (1) D. $\rightarrow(5)$ E. $\rightarrow$ (3)
A. Lanthanoid which shows +4 oxidation state is cerium.
${ }_{58} \mathrm{Ce}=[\mathrm{Xe}] 4 f^2 5 d^0 6 \mathrm{~s}^2 ;$ Oxidation state $=+3,+4$
B. Lanthanoid which can show +2 oxidation state is europium.
${ }_{63} \mathrm{Eu}=[\mathrm{Xe}] 4 f^7 5 d^0 6 \mathrm{~s}^2$; Oxidation state $=+2,+3$
C. Radioactive lanthanoid is promethium. It is the only synthetic (man-made) radioactive lanthanoid.
D. Lanthnoid which has $4 f^7$ electronic configuration in +3 oxidation state is gadolinium.
${ }_{64} \mathrm{Gd}=[\mathrm{Xe}] 4 f^7 5 d^1 6 s^2$; Oxidation state $=+3$
E. Lanthanoid which has $4 f^{14}$ electronic configuration in +3 oxidation state is lutetium
${ }_{71} \mathrm{Lu}=[\mathrm{Xe}] 4 f^{14} 5 d^1 6 s^2 ;$ Oxidation state $=+3$