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60
MCQ (Single Correct Answer)

Assertion (A) Separation of Zr and Hf is difficult.

Reason (R) Because Zr and Hf lie in the same group of the Periodic Table.

A
Both assertion and reason are true, and reason is the correct explanation of the assertion.
B
Both assertion and reason are true but reason is not the correct explanation of assertion.
C
Assertion is not true but reason is true.
D
Both assertion and reason are false.
61
MCQ (Single Correct Answer)

Assertion (A) Actinoids form relatively less stable complexes as compared to lanthanoids.

Reason (R) Actinoids can utilise their $5 f$ orbitals alongwith 6d orbitals in bonding but lanthanoids do not use their 4 f orbital for bonding.

A
Both assertion and reason are true, and reason is the correct explanation of the assertion.
B
Both assertion and reason are true but reason is not the correct explanation of assertion.
C
Assertion is not true but reason is true.
D
Both assertion and reason are false.
62
MCQ (Single Correct Answer)

Assertion (A) Cu cannot liberate hydrogen from acids.

Reason (R) Because it has positive electrode potential.

A
Both assertion and reason are true, and reason is the correct explanation of the assertion.
B
Both assertion and reason are true but reason is not the correct explanation of assertion.
C
Assertion is not true but reason is true.
D
Both assertion and reason are false.
63
MCQ (Single Correct Answer)

Assertion (A) The highest oxidation state of osmium is +8 .

Reason (R) Osmium is a 5 d -block element.

A
Both assertion and reason are true, and reason is the correct explanation of the assertion.
B
Both assertion and reason are true but reason is not the correct explanation of assertion.
C
Assertion is not true but reason is true.
D
Both assertion and reason are false.
64
Subjective

Identify A to E and also explain the reaction involved.

Explanation

The substances from $A$ to $E$ are

$$A=\mathrm{Cu} ; B=\mathrm{Cu}\left(\mathrm{NO}_3\right)_2 ; C=\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+} ; D=\mathrm{CO}_2 ; E=\mathrm{CaCO}_3$$

(i) $\mathrm{CuCO}_3 \xrightarrow{\Delta} \mathrm{CuO}+\mathrm{CO}_2] \times 2$

(ii) $2 \mathrm{CuO}+\mathrm{CuS} \longrightarrow \underset{[A]}{3 \mathrm{Cu}}+\mathrm{SO}_2$

(iii) $\underset{[A]}{\mathrm{Cu}}+4 \mathrm{HNO}_3$ (conc.) $\longrightarrow \underset{[B]}{\mathrm{Cu}\left(\mathrm{NO}_3\right)_2}+2 \mathrm{NO}+2 \mathrm{H}_2 \mathrm{O}$

(iv) $\underset{[B]}{\mathrm{Cu}^{2+}}+\mathrm{NH}_3 \longrightarrow \underset{\substack{\text { [C] (Blue solution)}}}{\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]}$

(v) $$Ca{(OH)_2} + \mathop {C{O_2}}\limits_{[D]} \buildrel {} \over \longrightarrow \mathop {CaC{O_3}}\limits_{[E]\,(Milky)} + {H_2}O$$

(vi) $\mathrm{CaCO}_3+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 \longrightarrow \mathrm{Ca}\left(\mathrm{HCO}_3\right)_2$