The Bohr model for the spectra of a H -atom
The Balmer series for the H -atom can be observed
Let $E_n=\frac{-1 m e^4}{8 \varepsilon_0^2 n^2 h^2}$ be the energy of the $n$th level of H -atom. If all the H -atoms are in the ground state and radiation of frequency $\frac{\left(E_2-E_1\right)}{h}$ falls on it,
The simple Bohr model is not applicable to $\mathrm{He}^4$ atom because
The mass of a H -atom is less than the sum of the masses of a proton and electron. Why is this?
Since, the difference in mass of a nucleus and its constituents, $\Delta M$, is called the mass defect and is given by
$$\Delta M=\left[Z m_p+(A-Z) m_n\right]-M$$
Also, the binding energy is given by $B=$ mass defect $(\Delta M) \times c^2$.
Thus, the mass of a H -atom is $m_p+m_e-\frac{B}{c^2}$, where $B \approx 13.6 \mathrm{eV}$ is the binding energy.