How do you account for the strong reducing power of lithium in aqueous solution?
Strong reducing power of lithium in aqueous solution can be understood in terms of electrode potential. Electrode potential is a measure of the tendency of an element to lose electrons in the aqueous solution. It mainly depends upon the following three factors i.e.,
(i) $\mathrm{Li}(\mathrm{s}) \xrightarrow[\text { Enthalpy }]{\text { Sublimation }} \mathrm{Li}(g)$
(ii) $\mathrm{Li}(g) \xrightarrow[\text { Enthalpy }]{\text { Ionisation }} \mathrm{Li}^{+}(g)+\mathrm{e}^{-}$
(iii) $\mathrm{Li}^{+}(g)+a q \longrightarrow \mathrm{Li}^{+}(a q)+$ enthalpy of hydration
With the small size of its ion, lithium has the highest hydration enthalpy. However, ionisation enthalpy of Li is highest among alkali metals but hydration enthalpy predominates over ionisation enthalpy.
Therefore, lithium is the strongest reducing agent in aqueous solution mainly because of its high enthalpy of hydration.
When heated in air, the alkali metals form various oxides. Mention the oxides formed by $\mathrm{Li}, \mathrm{Na}$ and K .
The reactivity of alkali metals towards oxygen increases on moving down the group with the increase in atomic size. Thus, Li forms only lithium oxide $\left(\mathrm{Li}_2 \mathrm{O}\right)$, sodium forms mainly sodium peroxide $\mathrm{Na}_2 \mathrm{O}_2$ along with a small amount of sodium oxide while potassium forms only potassium superoxide $\left(\mathrm{KO}_2\right)$.
$4 \mathrm{Li}+\mathrm{O}_2 \xrightarrow{\Delta} 2 \mathrm{Li}_2 \mathrm{O}$
$6 \mathrm{Na}+2 \mathrm{O}_2 \xrightarrow{\Delta} \underset{\substack{\text { Sodium peroxide } \\ \text { (major) }}}{\mathrm{Na}_2 \mathrm{O}_2}+\underset{\substack{\text { Monooxide } \\ \text { (minor) }}}{2 \mathrm{Na}_2 \mathrm{O}}$
$\mathrm{K}+\mathrm{O}_2 \xrightarrow{\Delta} \underset{\begin{array}{c}\text { Potassium } \\ \text { super oxides }\end{array}}{\mathrm{KO}_2}+\underset{\text { Peroxide }}{\mathrm{K}_2 \mathrm{O}_2}+\underset{\text { Monoxide }}{\mathrm{K}_2(\mathrm{O})}$
The superoxide, $\mathrm{O}_2^{-}$ion is stable only in presence of large cations such as $\mathrm{K}, \mathrm{Rb}$ etc.
Complete the following reactions
(i) $\mathrm{O}_2{ }^{2-}+\mathrm{H}_2 \mathrm{O} \longrightarrow$
(ii) $\mathrm{O}_2^{-}+\mathrm{H}_2 \mathrm{O} \longrightarrow$
$\mathrm{O}_2{ }^{2-}$ represents a peroxide ion
$\mathrm{O}_2^-$ represents a superoxide ion
(i) Peroxide ion react with water to form $\mathrm{H}_2 \mathrm{O}_2$
$$\mathrm{O_2^{2 - } + 2{H_2}O\buildrel {} \over \longrightarrow 2O{H^ - } + \mathop {{H_2}{O_2}}\limits_{Hydrogen\,peroxide}}$$
(ii) Superoxide ion react with water to form $\mathrm{H}_2 \mathrm{O}_2$ and $\mathrm{O}_2$
$2 \mathrm{O}_2^{-}+2 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{OH}^{-}+\underset{\substack{\text { Hydrogen } \\ \text { peroxide }}}{\mathrm{H}_2 \mathrm{O}_2}+\mathrm{O}_2$
Lithium resembles magnesium in some of its properties. Mention two such properties and give reasons for this resemblance.
Lithium resembles with magnesium as its charge size ratio is closer to Mg. Its resemblance with Mg is known as diagonal relationship.
Generally, the periodic properties show either increasing or decreasing trend along the group and vice-versa along the period which brought the diagonally situated elements to closer value.
Following characteristics can be noted
(i) Due to covalent nature, chlorides of Li and Mg are deliquescent and soluble in alcohol and pyridine.(ii) Carbonates of Li and Mg decompose on heating and liberate $\mathrm{CO}_2$
$\begin{aligned} \mathrm{Li}_2 \mathrm{CO}_3 & \longrightarrow \mathrm{Li}_2 \mathrm{O}+\mathrm{CO}_2 \\ \mathrm{MgCO}_3 & \longrightarrow \mathrm{MgO}+\mathrm{CO}_2\end{aligned}$
Name an element from group 2 which forms an amphoteric oxide and a water soluble sulphate.
An element from group 2 which forms an amphoteric oxide and a water soluble sulphate is beryllium.
Beryllium forms oxides of formula BeO . All other alkaline earth metal oxides are basic in nature. BeO is amphoteric in nature i.e., it reacts with acids and bases both.
$$\begin{gathered} \mathrm{Al}_2 \mathrm{O}_3+2 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaAlO}_2+\mathrm{H}_2 \mathrm{O} \\ \mathrm{Al}_2 \mathrm{O}_3+6 \mathrm{HCl} \longrightarrow 2 \mathrm{AlCl}_3+3 \mathrm{H}_2 \mathrm{O} \end{gathered}$$
Sulphate of beryllium is a white solid which crystallises as hydrated salts ( $\left.\mathrm{BeSO}_4 \cdot 4 \mathrm{H}_2 \mathrm{O}\right)$. $\mathrm{BeSO}_4$ is fairly soluble in water due to highest hydration energy in the group (small size). For $\mathrm{BeSO}_4$, hydration energy is more than lattice energy and so, they are readily soluble.