Thiosulphate reacts differently with iodine and bromine in the reactions given below
$$\begin{gathered} 2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-} \\ \mathrm{S}_2 \mathrm{O}_3^{2-}+2 \mathrm{Br}_2+5 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{SO}_4^{2-}+2 \mathrm{Br}^{-}+10 \mathrm{H}^{+} \end{gathered}$$
Which of the following statements justifies the above dual behaviour of thiosulphate?
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following is incorrect in this respect?
In which of the following compounds, an element exhibits two different oxidation states?
Which of the following arrangements represent increasing oxidation number of the central atom?
The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?