Which of the following statements is correct?
Which of the following statements is correct?
How can production of hydrogen from water gas be increased by using water gas shift reaction?
Water gas is produced when superheated steam is passed over red hot coke or coal at 1270 K in presence of nickel as catalyst.
$$\begin{aligned} & \mathrm{C}(\mathrm{s}) \\ & \text { Coke } \end{aligned}+\underset{\text { Steam }}{\mathrm{H}_2 \mathrm{O}(\mathrm{g})}+121.3 \mathrm{~kJ} \xrightarrow[\text { Nickel }]{1270 \mathrm{~K}} \underbrace{\mathrm{CO}(\mathrm{g})+\mathrm{H}_2(\mathrm{~g})}_{\text {Water gas }}$$
It is inconvinient to obtain pure $\mathrm{H}_2$ from water gas as CO is difficult to remove. Hence, to increase the production of $\mathrm{H}_2$ from water gas, CO is oxidised to $\mathrm{CO}_2$ by mixing it with more steam and passing the mixture over $\mathrm{FeCrO}_4$ catalyst at 673 K .
$\underbrace{\mathrm{CO}(g)+\mathrm{H}_2(g)}_{\text {Water gas }}+\mathrm{H}_{\text {Steam }}^{\mathrm{H}_2 \mathrm{O}}(\mathrm{g}) \xrightarrow[\mathrm{FeCrO}_4]{673 \mathrm{~K}} \mathrm{CO}_2(g)+2 \mathrm{H}_2(g)$
This is called water-gas shiff reaction. Carbon dioxide is removed by scrubbing with mixture of sodium arsenite solution or by passing the mixture through water under 30 atm pressure when $\mathrm{CO}_2$ dissolves leaving behind $\mathrm{H}_2$ which is collected.
What are metallic/interstitial hydrides? How do they differ from molecular hydrides?
Metallic/interstitial hydrides are formed by many $d$-block and $f$-block elements. These hydrides conduct heat and electricity.
Unlike saline hydride, they are almost always non-stoichiometric, being deficient in hydrogen. e.g., $\mathrm{LaH}_{2.87}, \mathrm{YbH}_{2.55}, \mathrm{TiH}_{1.5-1.8}, \mathrm{ZrH}_{1.3-1.75}, \mathrm{VH}_{0.56}, \mathrm{NiH}_{0.6-0.7}, \mathrm{PdH}_{0.6-0.8}$ etc. In such hydrides, the law of constant composition does not hold good.
Comparision between molecular and metallic hydrides
Molecular hydrides | Metallic hydrides |
---|---|
These are mainly formed by $p$-block elements and some $s$-block elements (Be and Mg ). | These are formed by group 3, 4, 5 (Sc, Ti, V, Y, Zr, $\mathrm{Nb}, \mathrm{La}, \mathrm{Hf}, \mathrm{Ta}, \mathrm{Ac}$ etc..) 10, 11, 12 (Pd, Cu, Zn etc..) and f-block elements (Ce, Eu, Yb, Th, U etc.) |
Those are usually volatile compounds having low melting and boiling point. | These are hard, have a metallic lustre. |
It conduct electricity. | These do not conduct electricity. |
Name the classes of hydrides to which $\mathrm{H}_2 \mathrm{O}, \mathrm{B}_2 \mathrm{H}_6$ and NaH belong.
$\mathrm{H}_2 \mathrm{O}-$ Covalent or molecular hydride (electron rich hydride).
$\mathrm{B}_2 \mathrm{H}_6-$ Covalent or molecular hydride (electron deficient hydride).
NaH - lonic or saline hydride.