If the sequence of nitrogen bases of the coding strand of DNA in a transcription unit is
$$ 5^{\prime} \text { - A T G A A T G - 3', } $$
the sequence of bases in its RNA transcript would be
$5^{\prime}-\mathrm{A} \cup \mathrm{GAA} \cup \mathrm{G}-3^{\prime}$
$5^{\prime}-\cup \mathrm{A} \subset \cup \cup \mathrm{A} \mathrm{C}-3^{\prime}$
$5^{\prime}-\mathrm{C} \mathrm{A} \cup \cup \mathrm{C} \mathrm{A} \cup-3^{\prime}$
$5^{\prime}-\mathrm{G} \cup \mathrm{A} A \mathrm{G} \cup \mathrm{A}-3^{\prime}$
The RNA polymerase holoenzyme transcribes
If the base sequence of a codon in $m R N A$ is $5^{\prime}-A \cup G-3^{\prime}$, the sequence of tRNA pairing with it must be
$5^{\prime}-\mathrm{UAC}-3^{\prime}$
$5^{\prime}-\mathrm{CAU}-3^{\prime}$
$5^{\prime}-\mathrm{AUG}-3^{\prime}$
$5^{\prime}-\mathrm{G} \cup \mathrm{A}-3^{\prime}$
The amino acid attaches to the $t$ RNA at its
5'-end
3'-end
Anti codon site
DHU loop
To initiate translation, the $m$ RNA first binds to
the smaller ribosomal sub-unit
the larger ribosomal sub-unit
the whole ribosome
No such specificity exists